Search a number
-
+
140341351155 = 3542089222293
BaseRepresentation
bin1000001010110011111…
…1110001001011110011
3111102020122000022111120
42002230333301023303
54244404341214110
6144245534113323
713065534542115
oct2025477611363
9442218008446
10140341351155
1154578041335
122324804b843
131030750a625
146b14ac73b5
1539b5b9c870
hex20acff12f3

140341351155 has 16 divisors (see below), whose sum is σ = 224552507040. Its totient is φ = 74846605568.

The previous prime is 140341351147. The next prime is 140341351169. The reversal of 140341351155 is 551153143041.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 140341351155 - 23 = 140341351147 is a prime.

It is a super-2 number, since 2×1403413511552 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 520189 + ... + 742481.

It is an arithmetic number, because the mean of its divisors is an integer number (14034531690).

Almost surely, 2140341351155 is an apocalyptic number.

140341351155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

140341351155 is a deficient number, since it is larger than the sum of its proper divisors (84211155885).

140341351155 is a wasteful number, since it uses less digits than its factorization.

140341351155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 264390.

The product of its (nonzero) digits is 18000, while the sum is 33.

Adding to 140341351155 its reverse (551153143041), we get a palindrome (691494494196).

The spelling of 140341351155 in words is "one hundred forty billion, three hundred forty-one million, three hundred fifty-one thousand, one hundred fifty-five".

Divisors: 1 3 5 15 42089 126267 210445 222293 631335 666879 1111465 3334395 9356090077 28068270231 46780450385 140341351155