Base | Representation |
---|---|
bin | 1100110000111001011110… |
… | …1011110011110011101010 |
3 | 1211200122201201220101021212 |
4 | 3030032113223303303222 |
5 | 3314414021432000132 |
6 | 45503120204033122 |
7 | 2645636430143621 |
oct | 314162753636352 |
9 | 54618651811255 |
10 | 14034203000042 |
11 | 45209657a4875 |
12 | 16a7b0a2327a2 |
13 | 7aa55c005404 |
14 | 36738ab906b8 |
15 | 1950dd9ea5b2 |
hex | cc397af3cea |
14034203000042 has 4 divisors (see below), whose sum is σ = 21051304500066. Its totient is φ = 7017101500020.
The previous prime is 14034203000011. The next prime is 14034203000053. The reversal of 14034203000042 is 24000030243041.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11299608297121 + 2734594702921 = 3361489^2 + 1653661^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14034202999981 and 14034203000017.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3508550750009 + ... + 3508550750012.
Almost surely, 214034203000042 is an apocalyptic number.
14034203000042 is a deficient number, since it is larger than the sum of its proper divisors (7017101500024).
14034203000042 is an equidigital number, since it uses as much as digits as its factorization.
14034203000042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7017101500023.
The product of its (nonzero) digits is 2304, while the sum is 23.
Adding to 14034203000042 its reverse (24000030243041), we get a palindrome (38034233243083).
The spelling of 14034203000042 in words is "fourteen trillion, thirty-four billion, two hundred three million, forty-two", and thus it is an aban number.
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