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14034203000042 = 27017101500021
BaseRepresentation
bin1100110000111001011110…
…1011110011110011101010
31211200122201201220101021212
43030032113223303303222
53314414021432000132
645503120204033122
72645636430143621
oct314162753636352
954618651811255
1014034203000042
1145209657a4875
1216a7b0a2327a2
137aa55c005404
1436738ab906b8
151950dd9ea5b2
hexcc397af3cea

14034203000042 has 4 divisors (see below), whose sum is σ = 21051304500066. Its totient is φ = 7017101500020.

The previous prime is 14034203000011. The next prime is 14034203000053. The reversal of 14034203000042 is 24000030243041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11299608297121 + 2734594702921 = 3361489^2 + 1653661^2 .

It is a junction number, because it is equal to n+sod(n) for n = 14034202999981 and 14034203000017.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3508550750009 + ... + 3508550750012.

Almost surely, 214034203000042 is an apocalyptic number.

14034203000042 is a deficient number, since it is larger than the sum of its proper divisors (7017101500024).

14034203000042 is an equidigital number, since it uses as much as digits as its factorization.

14034203000042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7017101500023.

The product of its (nonzero) digits is 2304, while the sum is 23.

Adding to 14034203000042 its reverse (24000030243041), we get a palindrome (38034233243083).

The spelling of 14034203000042 in words is "fourteen trillion, thirty-four billion, two hundred three million, forty-two", and thus it is an aban number.

Divisors: 1 2 7017101500021 14034203000042