1403421311341 has 4 divisors (see below), whose sum is σ = 1603910070112. Its totient is φ = 1202932552572.

The previous prime is 1403421311339. The next prime is 1403421311351. The reversal of 1403421311341 is 1431131243041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1403421311341 - 2¹ = 1403421311339 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1403421311351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100244379375 + ... + 100244379388.

It is an arithmetic number, because the mean of its divisors is an integer number (400977517528).

Almost surely, 2^{1403421311341} is an apocalyptic number.

It is an amenable number.

1403421311341 is a deficient number, since it is larger than the sum of its proper divisors (200488758771).

1403421311341 is an equidigital number, since it uses as much as digits as its factorization.

1403421311341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 200488758770.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 1403421311341 its reverse (1431131243041), we get a palindrome (2834552554382).

The spelling of 1403421311341 in words is "one trillion, four hundred three billion, four hundred twenty-one million, three hundred eleven thousand, three hundred forty-one".