Base | Representation |
---|---|
bin | 1100110000111011000101… |
… | …0001100111101101001111 |
3 | 1211200200211122210020012212 |
4 | 3030032301101213231033 |
5 | 3314420411334423401 |
6 | 45503230542221035 |
7 | 2645653162404515 |
oct | 314166121475517 |
9 | 54620748706185 |
10 | 14034632342351 |
11 | 4521066091025 |
12 | 16a8009b8477b |
13 | 7aa5c9c4b50a |
14 | 3673cbbd24b5 |
15 | 195116557dbb |
hex | cc3b1467b4f |
14034632342351 has 4 divisors (see below), whose sum is σ = 14376940448304. Its totient is φ = 13692324236400.
The previous prime is 14034632342249. The next prime is 14034632342363. The reversal of 14034632342351 is 15324323643041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14034632342351 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (41), and also a Moran number because the ratio is a prime number: 342308105911 = 14034632342351 / (1 + 4 + 0 + 3 + 4 + 6 + 3 + 2 + 3 + 4 + 2 + 3 + 5 + 1).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14034632342299 and 14034632342308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14034632302351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171154052915 + ... + 171154052996.
It is an arithmetic number, because the mean of its divisors is an integer number (3594235112076).
Almost surely, 214034632342351 is an apocalyptic number.
14034632342351 is a deficient number, since it is larger than the sum of its proper divisors (342308105953).
14034632342351 is an equidigital number, since it uses as much as digits as its factorization.
14034632342351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 342308105952.
The product of its (nonzero) digits is 622080, while the sum is 41.
Adding to 14034632342351 its reverse (15324323643041), we get a palindrome (29358955985392).
The spelling of 14034632342351 in words is "fourteen trillion, thirty-four billion, six hundred thirty-two million, three hundred forty-two thousand, three hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •