140351233531253 has 4 divisors (see below), whose sum is σ = 140496374414880. Its totient is φ = 140206092647628.

The previous prime is 140351233531219. The next prime is 140351233531283. The reversal of 140351233531253 is 352135332153041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140351233531253 - 2¹⁰ = 140351233530229 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 140351233531253.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140351233531283) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72570440363 + ... + 72570442296.

It is an arithmetic number, because the mean of its divisors is an integer number (35124093603720).

Almost surely, 2^{140351233531253} is an apocalyptic number.

It is an amenable number.

140351233531253 is a deficient number, since it is larger than the sum of its proper divisors (145140883627).

140351233531253 is an equidigital number, since it uses as much as digits as its factorization.

140351233531253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 145140883626.

The product of its (nonzero) digits is 486000, while the sum is 41.

Adding to 140351233531253 its reverse (352135332153041), we get a palindrome (492486565684294).

The spelling of 140351233531253 in words is "one hundred forty trillion, three hundred fifty-one billion, two hundred thirty-three million, five hundred thirty-one thousand, two hundred fifty-three".