Base | Representation |
---|---|
bin | 1100110000111101100111… |
… | …0010011001101101010001 |
3 | 1211200202121000201122201010 |
4 | 3030033121302121231101 |
5 | 3314423304334240101 |
6 | 45503422222201133 |
7 | 2646006054534033 |
oct | 314173162315521 |
9 | 54622530648633 |
10 | 14035312024401 |
11 | 4521384813228 |
12 | 16a81797231a9 |
13 | 7aa6a79c5845 |
14 | 36745419bc53 |
15 | 1951560652d6 |
hex | cc3d9c99b51 |
14035312024401 has 16 divisors (see below), whose sum is σ = 18748874527808. Its totient is φ = 9339313089600.
The previous prime is 14035312024399. The next prime is 14035312024427. The reversal of 14035312024401 is 10442021353041.
It is not a de Polignac number, because 14035312024401 - 21 = 14035312024399 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14035312024451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 68708346 + ... + 68912316.
It is an arithmetic number, because the mean of its divisors is an integer number (1171804657988).
Almost surely, 214035312024401 is an apocalyptic number.
It is an amenable number.
14035312024401 is a deficient number, since it is larger than the sum of its proper divisors (4713562503407).
14035312024401 is a wasteful number, since it uses less digits than its factorization.
14035312024401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 246912.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 14035312024401 its reverse (10442021353041), we get a palindrome (24477333377442).
The spelling of 14035312024401 in words is "fourteen trillion, thirty-five billion, three hundred twelve million, twenty-four thousand, four hundred one".
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