14040021311441 has 4 divisors (see below), whose sum is σ = 14040059158452. Its totient is φ = 14039983464432.

The previous prime is 14040021311389. The next prime is 14040021311447. The reversal of 14040021311441 is 14411312004041.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9827572930816 + 4212448380625 = 3134896^2 + 2052425^2 .

It is a cyclic number.

It is not a de Polignac number, because 14040021311441 - 2¹⁴ = 14040021295057 is a prime.

It is a super-4 number, since 4×14040021311441⁴ (a number of 54 digits) contains 4444 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14040021311441.

It is not an unprimeable number, because it can be changed into a prime (14040021311447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18361490 + ... + 19110843.

It is an arithmetic number, because the mean of its divisors is an integer number (3510014789613).

Almost surely, 2^{14040021311441} is an apocalyptic number.

It is an amenable number.

14040021311441 is a deficient number, since it is larger than the sum of its proper divisors (37847011).

14040021311441 is an equidigital number, since it uses as much as digits as its factorization.

14040021311441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37847010.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 14040021311441 its reverse (14411312004041), we get a palindrome (28451333315482).

The spelling of 14040021311441 in words is "fourteen trillion, forty billion, twenty-one million, three hundred eleven thousand, four hundred forty-one".