14040111301 has 4 divisors (see below), whose sum is σ = 14524253100. Its totient is φ = 13555969504.

The previous prime is 14040111289. The next prime is 14040111307. The reversal of 14040111301 is 10311104041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10332519201 + 3707592100 = 101649^2 + 60890^2 .

It is a cyclic number.

It is not a de Polignac number, because 14040111301 - 2⁵ = 14040111269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14040111307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242070856 + ... + 242070913.

It is an arithmetic number, because the mean of its divisors is an integer number (3631063275).

Almost surely, 2^14040111301 is an apocalyptic number.

It is an amenable number.

14040111301 is a deficient number, since it is larger than the sum of its proper divisors (484141799).

14040111301 is an equidigital number, since it uses as much as digits as its factorization.

14040111301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 484141798.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 14040111301 its reverse (10311104041), we get a palindrome (24351215342).

The spelling of 14040111301 in words is "fourteen billion, forty million, one hundred eleven thousand, three hundred one".