14040114132133 has 4 divisors (see below), whose sum is σ = 14040122065920. Its totient is φ = 14040106198348.

The previous prime is 14040114132131. The next prime is 14040114132169. The reversal of 14040114132133 is 33123141104041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 14040114132133 - 2¹ = 14040114132131 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14040114132131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29916 + ... + 5299162.

It is an arithmetic number, because the mean of its divisors is an integer number (3510030516480).

Almost surely, 2^{14040114132133} is an apocalyptic number.

It is an amenable number.

14040114132133 is a deficient number, since it is larger than the sum of its proper divisors (7933787).

14040114132133 is an equidigital number, since it uses as much as digits as its factorization.

14040114132133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7933786.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 14040114132133 its reverse (33123141104041), we get a palindrome (47163255236174).

The spelling of 14040114132133 in words is "fourteen trillion, forty billion, one hundred fourteen million, one hundred thirty-two thousand, one hundred thirty-three".