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140401231441 = 236104401367
BaseRepresentation
bin1000001011000010010…
…0001100011001010001
3111102101210200112210221
42002300210030121101
54300020203401231
6144255513353041
713100162530162
oct2026044143121
9442353615727
10140401231441
11545a8920279
1223264108781
1310316a44c53
146b1ca33769
1539bb079d11
hex20b090c651

140401231441 has 4 divisors (see below), whose sum is σ = 146505632832. Its totient is φ = 134296830052.

The previous prime is 140401231427. The next prime is 140401231457. The reversal of 140401231441 is 144132104041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140401231441 - 25 = 140401231409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140401231471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3052200661 + ... + 3052200706.

It is an arithmetic number, because the mean of its divisors is an integer number (36626408208).

Almost surely, 2140401231441 is an apocalyptic number.

It is an amenable number.

140401231441 is a deficient number, since it is larger than the sum of its proper divisors (6104401391).

140401231441 is an equidigital number, since it uses as much as digits as its factorization.

140401231441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6104401390.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 140401231441 its reverse (144132104041), we get a palindrome (284533335482).

The spelling of 140401231441 in words is "one hundred forty billion, four hundred one million, two hundred thirty-one thousand, four hundred forty-one".

Divisors: 1 23 6104401367 140401231441