Base | Representation |
---|---|
bin | 1100110001001111100010… |
… | …0111000001111101011101 |
3 | 1211201020000101111122200111 |
4 | 3030103320213001331131 |
5 | 3320013133232321131 |
6 | 45505535521530021 |
7 | 2646236235536143 |
oct | 314237047017535 |
9 | 54636011448614 |
10 | 14040124104541 |
11 | 4523424039267 |
12 | 16a90a11a3911 |
13 | 7aac93939742 |
14 | 36778d303593 |
15 | 19533874bab1 |
hex | cc4f89c1f5d |
14040124104541 has 4 divisors (see below), whose sum is σ = 14779078004800. Its totient is φ = 13301170204284.
The previous prime is 14040124104509. The next prime is 14040124104659. The reversal of 14040124104541 is 14540142104041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14040124104541 - 25 = 14040124104509 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14040124102541) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 369476950101 + ... + 369476950138.
It is an arithmetic number, because the mean of its divisors is an integer number (3694769501200).
Almost surely, 214040124104541 is an apocalyptic number.
It is an amenable number.
14040124104541 is a deficient number, since it is larger than the sum of its proper divisors (738953900259).
14040124104541 is an equidigital number, since it uses as much as digits as its factorization.
14040124104541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 738953900258.
The product of its (nonzero) digits is 10240, while the sum is 31.
Adding to 14040124104541 its reverse (14540142104041), we get a palindrome (28580266208582).
The spelling of 14040124104541 in words is "fourteen trillion, forty billion, one hundred twenty-four million, one hundred four thousand, five hundred forty-one".
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