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14040130033453 = 191096779396443
BaseRepresentation
bin1100110001001111100011…
…1101101001011100101101
31211201020000210122212121211
43030103320331221130231
53320013141242032303
645505540252554421
72646236340121456
oct314237075513455
954636023585554
1014040130033453
114523427418797
1216a90a3182a11
137aac94c34284
1436779000812d
1519533901d66d
hexcc4f8f6972d

14040130033453 has 8 divisors (see below), whose sum is σ = 14914672176800. Its totient is φ = 13179146683248.

The previous prime is 14040130033427. The next prime is 14040130033469. The reversal of 14040130033453 is 35433003104041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14040130033453 - 225 = 14040096479021 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14040130033483) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3389696151 + ... + 3389700292.

It is an arithmetic number, because the mean of its divisors is an integer number (1864334022100).

Almost surely, 214040130033453 is an apocalyptic number.

It is an amenable number.

14040130033453 is a deficient number, since it is larger than the sum of its proper divisors (874542143347).

14040130033453 is a wasteful number, since it uses less digits than its factorization.

14040130033453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6779396571.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 14040130033453 its reverse (35433003104041), we get a palindrome (49473133137494).

The spelling of 14040130033453 in words is "fourteen trillion, forty billion, one hundred thirty million, thirty-three thousand, four hundred fifty-three".

Divisors: 1 19 109 2071 6779396443 128808532417 738954212287 14040130033453