140402511155441 has 4 divisors (see below), whose sum is σ = 140413487832384. Its totient is φ = 140391534478500.

The previous prime is 140402511155437. The next prime is 140402511155563. The reversal of 140402511155441 is 144551115204041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140402511155441 - 2² = 140402511155437 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140402511155395 and 140402511155404.

It is not an unprimeable number, because it can be changed into a prime (140402513155441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5488319285 + ... + 5488344866.

It is an arithmetic number, because the mean of its divisors is an integer number (35103371958096).

Almost surely, 2^{140402511155441} is an apocalyptic number.

It is an amenable number.

140402511155441 is a deficient number, since it is larger than the sum of its proper divisors (10976676943).

140402511155441 is a wasteful number, since it uses less digits than its factorization.

140402511155441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10976676942.

The product of its (nonzero) digits is 64000, while the sum is 38.

Adding to 140402511155441 its reverse (144551115204041), we get a palindrome (284953626359482).

The spelling of 140402511155441 in words is "one hundred forty trillion, four hundred two billion, five hundred eleven million, one hundred fifty-five thousand, four hundred forty-one".