1404030440131 has 4 divisors (see below), whose sum is σ = 1531669571064. Its totient is φ = 1276391309200.

The previous prime is 1404030440123. The next prime is 1404030440171. The reversal of 1404030440131 is 1310440304041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1404030440131 - 2³ = 1404030440123 is a prime.

It is a super-2 number, since 2×1404030440131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1404030440096 and 1404030440105.

It is not an unprimeable number, because it can be changed into a prime (1404030440171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63819565450 + ... + 63819565471.

It is an arithmetic number, because the mean of its divisors is an integer number (382917392766).

Almost surely, 2^{1404030440131} is an apocalyptic number.

1404030440131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1404030440131 is a deficient number, since it is larger than the sum of its proper divisors (127639130933).

1404030440131 is a wasteful number, since it uses less digits than its factorization.

1404030440131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 127639130932.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1404030440131 its reverse (1310440304041), we get a palindrome (2714470744172).

The spelling of 1404030440131 in words is "one trillion, four hundred four billion, thirty million, four hundred forty thousand, one hundred thirty-one".