14040322425341 has 4 divisors (see below), whose sum is σ = 14040485715900. Its totient is φ = 14040159134784.

The previous prime is 14040322425301. The next prime is 14040322425347. The reversal of 14040322425341 is 14352422304041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10902074745241 + 3138247680100 = 3301829^2 + 1771510^2 .

It is a cyclic number.

It is not a de Polignac number, because 14040322425341 - 2³⁰ = 14039248683517 is a prime.

It is a super-3 number, since 3×14040322425341³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14040322425347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81516236 + ... + 81688293.

It is an arithmetic number, because the mean of its divisors is an integer number (3510121428975).

Almost surely, 2^{14040322425341} is an apocalyptic number.

It is an amenable number.

14040322425341 is a deficient number, since it is larger than the sum of its proper divisors (163290559).

14040322425341 is an equidigital number, since it uses as much as digits as its factorization.

14040322425341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163290558.

The product of its (nonzero) digits is 92160, while the sum is 35.

Adding to 14040322425341 its reverse (14352422304041), we get a palindrome (28392744729382).

The spelling of 14040322425341 in words is "fourteen trillion, forty billion, three hundred twenty-two million, four hundred twenty-five thousand, three hundred forty-one".