140411212043413 has 4 divisors (see below), whose sum is σ = 140433161590540. Its totient is φ = 140389262496288.

The previous prime is 140411212043369. The next prime is 140411212043419. The reversal of 140411212043413 is 314340212114041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 75721636505124 + 64689575538289 = 8701818^2 + 8042983^2 .

It is a cyclic number.

It is not a de Polignac number, because 140411212043413 - 2⁹ = 140411212042901 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140411212043419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10974763968 + ... + 10974776761.

It is an arithmetic number, because the mean of its divisors is an integer number (35108290397635).

Almost surely, 2^{140411212043413} is an apocalyptic number.

It is an amenable number.

140411212043413 is a deficient number, since it is larger than the sum of its proper divisors (21949547127).

140411212043413 is an equidigital number, since it uses as much as digits as its factorization.

140411212043413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21949547126.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 140411212043413 its reverse (314340212114041), we get a palindrome (454751424157454).

The spelling of 140411212043413 in words is "one hundred forty trillion, four hundred eleven billion, two hundred twelve million, forty-three thousand, four hundred thirteen".