1404112121 has 4 divisors (see below), whose sum is σ = 1404190032. Its totient is φ = 1404034212.

The previous prime is 1404112097. The next prime is 1404112187. The reversal of 1404112121 is 1212114041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 1212114041 = 1667 ⋅727123.

It is a cyclic number.

It is not a de Polignac number, because 1404112121 - 2⁶ = 1404112057 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1404112121.

It is not an unprimeable number, because it can be changed into a prime (1404102121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3506 + ... + 53108.

It is an arithmetic number, because the mean of its divisors is an integer number (351047508).

Almost surely, 2^1404112121 is an apocalyptic number.

It is an amenable number.

1404112121 is a deficient number, since it is larger than the sum of its proper divisors (77911).

1404112121 is an equidigital number, since it uses as much as digits as its factorization.

1404112121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77910.

The product of its (nonzero) digits is 64, while the sum is 17.

The square root of 1404112121 is about 37471.4841045828. The cubic root of 1404112121 is about 1119.7831534372.

Adding to 1404112121 its reverse (1212114041), we get a palindrome (2616226162).

It can be divided in two parts, 14041 and 12121, that added together give a palindrome (26162).

The spelling of 1404112121 in words is "one billion, four hundred four million, one hundred twelve thousand, one hundred twenty-one".