14041130210213 has 4 divisors (see below), whose sum is σ = 14383596800748. Its totient is φ = 13698663619680.

The previous prime is 14041130210201. The next prime is 14041130210257. The reversal of 14041130210213 is 31201203114041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 777417814369 + 13263712395844 = 881713^2 + 3641938^2 .

It is a cyclic number.

It is not a de Polignac number, because 14041130210213 - 2¹⁶ = 14041130144677 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14041130210273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171233295206 + ... + 171233295287.

It is an arithmetic number, because the mean of its divisors is an integer number (3595899200187).

Almost surely, 2^{14041130210213} is an apocalyptic number.

It is an amenable number.

14041130210213 is a deficient number, since it is larger than the sum of its proper divisors (342466590535).

14041130210213 is an equidigital number, since it uses as much as digits as its factorization.

14041130210213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 342466590534.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 14041130210213 its reverse (31201203114041), we get a palindrome (45242333324254).

The spelling of 14041130210213 in words is "fourteen trillion, forty-one billion, one hundred thirty million, two hundred ten thousand, two hundred thirteen".