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14041223012113 = 1112710050982829
BaseRepresentation
bin1100110001010011101000…
…0111000001111100010001
31211201022211222021221110221
43030110322013001330101
53320022411042341423
645510240535153041
72646305411232253
oct314247207017421
954638758257427
1014041223012113
114523938377840
1216a9349215781
137ab10a4c70cb
14367855239cd3
1519539ee68e5d
hexcc53a1c1f11

14041223012113 has 8 divisors (see below), whose sum is σ = 15438309626880. Its totient is φ = 12664238363280.

The previous prime is 14041223012057. The next prime is 14041223012119. The reversal of 14041223012113 is 31121032214041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14041223012113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14041223012119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5025490018 + ... + 5025492811.

It is an arithmetic number, because the mean of its divisors is an integer number (1929788703360).

Almost surely, 214041223012113 is an apocalyptic number.

It is an amenable number.

14041223012113 is a deficient number, since it is larger than the sum of its proper divisors (1397086614767).

14041223012113 is a wasteful number, since it uses less digits than its factorization.

14041223012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10050982967.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14041223012113 its reverse (31121032214041), we get a palindrome (45162255226154).

The spelling of 14041223012113 in words is "fourteen trillion, forty-one billion, two hundred twenty-three million, twelve thousand, one hundred thirteen".

Divisors: 1 11 127 1397 10050982829 110560811119 1276474819283 14041223012113