14041413403 has 4 divisors (see below), whose sum is σ = 14041931400. Its totient is φ = 14040895408.

The previous prime is 14041413391. The next prime is 14041413409. The reversal of 14041413403 is 30431414041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14041413403 - 2¹³ = 14041405211 is a prime.

It is a super-2 number, since 2×14041413403² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14041413409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 215953 + ... + 273346.

It is an arithmetic number, because the mean of its divisors is an integer number (3510482850).

Almost surely, 2^14041413403 is an apocalyptic number.

14041413403 is a deficient number, since it is larger than the sum of its proper divisors (517997).

14041413403 is an equidigital number, since it uses as much as digits as its factorization.

14041413403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 517996.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14041413403 its reverse (30431414041), we get a palindrome (44472827444).

The spelling of 14041413403 in words is "fourteen billion, forty-one million, four hundred thirteen thousand, four hundred three".