1404143623 has 4 divisors (see below), whose sum is σ = 1415200000. Its totient is φ = 1393087248.

The previous prime is 1404143621. The next prime is 1404143627. The reversal of 1404143623 is 3263414041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3263414041 = 23 ⋅141887567.

It is a cyclic number.

It is not a de Polignac number, because 1404143623 - 2¹ = 1404143621 is a prime.

It is a super-2 number, since 2×1404143623² = 3943238628023132258, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1404143591 and 1404143600.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1404143621) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5527998 + ... + 5528251.

It is an arithmetic number, because the mean of its divisors is an integer number (353800000).

Almost surely, 2^1404143623 is an apocalyptic number.

1404143623 is a deficient number, since it is larger than the sum of its proper divisors (11056377).

1404143623 is a wasteful number, since it uses less digits than its factorization.

1404143623 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11056376.

The product of its (nonzero) digits is 6912, while the sum is 28.

The square root of 1404143623 is about 37471.9044485332. The cubic root of 1404143623 is about 1119.7915276842.

Adding to 1404143623 its reverse (3263414041), we get a palindrome (4667557664).

The spelling of 1404143623 in words is "one billion, four hundred four million, one hundred forty-three thousand, six hundred twenty-three".