140420003431333 has 4 divisors (see below), whose sum is σ = 144949680961408. Its totient is φ = 135890325901260.

The previous prime is 140420003431303. The next prime is 140420003431349. The reversal of 140420003431333 is 333134300024041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140420003431333 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (31), and also a Moran number because the ratio is a prime number: 4529677530043 = 140420003431333 / (1 + 4 + 0 + 4 + 2 + 0 + 0 + 0 + 3 + 4 + 3 + 1 + 3 + 3 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140420003431295 and 140420003431304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140420003431303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2264838764991 + ... + 2264838765052.

It is an arithmetic number, because the mean of its divisors is an integer number (36237420240352).

Almost surely, 2^{140420003431333} is an apocalyptic number.

It is an amenable number.

140420003431333 is a deficient number, since it is larger than the sum of its proper divisors (4529677530075).

140420003431333 is an equidigital number, since it uses as much as digits as its factorization.

140420003431333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4529677530074.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 140420003431333 its reverse (333134300024041), we get a palindrome (473554303455374).

The spelling of 140420003431333 in words is "one hundred forty trillion, four hundred twenty billion, three million, four hundred thirty-one thousand, three hundred thirty-three".