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140420113 = 167840839
BaseRepresentation
bin10000101111010…
…10010000010001
3100210020002011221
420113222100101
5241421420423
621533405041
73323360041
oct1027522021
9323202157
10140420113
1172299789
123b039781
1323126632
1414913721
15c4dae5d
hex85ea411

140420113 has 4 divisors (see below), whose sum is σ = 141261120. Its totient is φ = 139579108.

The previous prime is 140420107. The next prime is 140420191. The reversal of 140420113 is 311024041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140420113 - 25 = 140420081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140420713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 420253 + ... + 420586.

It is an arithmetic number, because the mean of its divisors is an integer number (35315280).

Almost surely, 2140420113 is an apocalyptic number.

It is an amenable number.

140420113 is a deficient number, since it is larger than the sum of its proper divisors (841007).

140420113 is an equidigital number, since it uses as much as digits as its factorization.

140420113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 841006.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 140420113 is about 11849.8992822724. The cubic root of 140420113 is about 519.7682806336.

Adding to 140420113 its reverse (311024041), we get a palindrome (451444154).

The spelling of 140420113 in words is "one hundred forty million, four hundred twenty thousand, one hundred thirteen".

Divisors: 1 167 840839 140420113