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14042011333 = 72006001619
BaseRepresentation
bin11010001001111100…
…00001011011000101
31100020121112002021211
431010332001123011
5212224223330313
610241213011421
71004655061360
oct150476013305
940217462254
1014042011333
115a56392a49
12287a783b71
13142a22b05c
14972cd10d7
15572b80e3d
hex344f816c5

14042011333 has 4 divisors (see below), whose sum is σ = 16048012960. Its totient is φ = 12036009708.

The previous prime is 14042011301. The next prime is 14042011337. The reversal of 14042011333 is 33311024041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14042011333 - 25 = 14042011301 is a prime.

It is a super-2 number, since 2×140420113332 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14042011337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1003000803 + ... + 1003000816.

It is an arithmetic number, because the mean of its divisors is an integer number (4012003240).

Almost surely, 214042011333 is an apocalyptic number.

It is an amenable number.

14042011333 is a deficient number, since it is larger than the sum of its proper divisors (2006001627).

14042011333 is an equidigital number, since it uses as much as digits as its factorization.

14042011333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2006001626.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 14042011333 its reverse (33311024041), we get a palindrome (47353035374).

The spelling of 14042011333 in words is "fourteen billion, forty-two million, eleven thousand, three hundred thirty-three".

Divisors: 1 7 2006001619 14042011333