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14042045314211 = 52027269899193
BaseRepresentation
bin1100110001010110101100…
…0111110111010010100011
31211201101222021121012220012
43030111223013313102203
53320031102100023321
645510454312035135
72646334654543415
oct314255307672243
954641867535805
1014042045314211
11452421a560552
1216a9538692aab
137ab20b9881b5
143678d252c9b5
151953ec24905b
hexcc56b1f74a3

14042045314211 has 4 divisors (see below), whose sum is σ = 14042315265432. Its totient is φ = 14041775362992.

The previous prime is 14042045314207. The next prime is 14042045314217. The reversal of 14042045314211 is 11241354024041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14042045314211 - 22 = 14042045314207 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14042045314217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134897570 + ... + 135001623.

It is an arithmetic number, because the mean of its divisors is an integer number (3510578816358).

Almost surely, 214042045314211 is an apocalyptic number.

14042045314211 is a deficient number, since it is larger than the sum of its proper divisors (269951221).

14042045314211 is an equidigital number, since it uses as much as digits as its factorization.

14042045314211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 269951220.

The product of its (nonzero) digits is 15360, while the sum is 32.

Adding to 14042045314211 its reverse (11241354024041), we get a palindrome (25283399338252).

The spelling of 14042045314211 in words is "fourteen trillion, forty-two billion, forty-five million, three hundred fourteen thousand, two hundred eleven".

Divisors: 1 52027 269899193 14042045314211