140421120433 has 4 divisors (see below), whose sum is σ = 153186676848. Its totient is φ = 127655564020.

The previous prime is 140421120403. The next prime is 140421120533. The reversal of 140421120433 is 334021124041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140421120433 - 2⁵ = 140421120401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140421120398 and 140421120407.

It is not an unprimeable number, because it can be changed into a prime (140421120403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6382778191 + ... + 6382778212.

It is an arithmetic number, because the mean of its divisors is an integer number (38296669212).

Almost surely, 2^140421120433 is an apocalyptic number.

It is an amenable number.

140421120433 is a deficient number, since it is larger than the sum of its proper divisors (12765556415).

140421120433 is a wasteful number, since it uses less digits than its factorization.

140421120433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12765556414.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 140421120433 its reverse (334021124041), we get a palindrome (474442244474).

The spelling of 140421120433 in words is "one hundred forty billion, four hundred twenty-one million, one hundred twenty thousand, four hundred thirty-three".