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140422155533 = 1112765650503
BaseRepresentation
bin1000001011000111010…
…0000000110100001101
3111102110021001121021022
42002301310000310031
54300041032434113
6144301542043525
713100535425312
oct2026164006415
9442407047238
10140422155533
1154609711910
122326b1195a5
131031b18cb7a
146b2171cd09
1539bcd0e908
hex20b1d00d0d

140422155533 has 4 divisors (see below), whose sum is σ = 153187806048. Its totient is φ = 127656505020.

The previous prime is 140422155493. The next prime is 140422155551. The reversal of 140422155533 is 335551224041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-140422155533 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140422155493 and 140422155502.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140422155563) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6382825241 + ... + 6382825262.

It is an arithmetic number, because the mean of its divisors is an integer number (38296951512).

Almost surely, 2140422155533 is an apocalyptic number.

It is an amenable number.

140422155533 is a deficient number, since it is larger than the sum of its proper divisors (12765650515).

140422155533 is a wasteful number, since it uses less digits than its factorization.

140422155533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12765650514.

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 140422155533 its reverse (335551224041), we get a palindrome (475973379574).

The spelling of 140422155533 in words is "one hundred forty billion, four hundred twenty-two million, one hundred fifty-five thousand, five hundred thirty-three".

Divisors: 1 11 12765650503 140422155533