Base | Representation |
---|---|
bin | 1000001011000111010… |
… | …0000000110100001101 |
3 | 111102110021001121021022 |
4 | 2002301310000310031 |
5 | 4300041032434113 |
6 | 144301542043525 |
7 | 13100535425312 |
oct | 2026164006415 |
9 | 442407047238 |
10 | 140422155533 |
11 | 54609711910 |
12 | 2326b1195a5 |
13 | 1031b18cb7a |
14 | 6b2171cd09 |
15 | 39bcd0e908 |
hex | 20b1d00d0d |
140422155533 has 4 divisors (see below), whose sum is σ = 153187806048. Its totient is φ = 127656505020.
The previous prime is 140422155493. The next prime is 140422155551. The reversal of 140422155533 is 335551224041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a de Polignac number, because none of the positive numbers 2k-140422155533 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 140422155493 and 140422155502.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140422155563) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6382825241 + ... + 6382825262.
It is an arithmetic number, because the mean of its divisors is an integer number (38296951512).
Almost surely, 2140422155533 is an apocalyptic number.
It is an amenable number.
140422155533 is a deficient number, since it is larger than the sum of its proper divisors (12765650515).
140422155533 is a wasteful number, since it uses less digits than its factorization.
140422155533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12765650514.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 140422155533 its reverse (335551224041), we get a palindrome (475973379574).
The spelling of 140422155533 in words is "one hundred forty billion, four hundred twenty-two million, one hundred fifty-five thousand, five hundred thirty-three".
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