14042431441131 has 4 divisors (see below), whose sum is σ = 18723241921512. Its totient is φ = 9361620960752.

The previous prime is 14042431441127. The next prime is 14042431441169. The reversal of 14042431441131 is 13114413424041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14042431441131 - 2² = 14042431441127 is a prime.

It is a super-2 number, since 2×14042431441131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14042431441092 and 14042431441101.

It is not an unprimeable number, because it can be changed into a prime (14042431442131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2340405240186 + ... + 2340405240191.

It is an arithmetic number, because the mean of its divisors is an integer number (4680810480378).

Almost surely, 2^{14042431441131} is an apocalyptic number.

14042431441131 is a deficient number, since it is larger than the sum of its proper divisors (4680810480381).

14042431441131 is an equidigital number, since it uses as much as digits as its factorization.

14042431441131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4680810480380.

The product of its (nonzero) digits is 18432, while the sum is 33.

Adding to 14042431441131 its reverse (13114413424041), we get a palindrome (27156844865172).

The spelling of 14042431441131 in words is "fourteen trillion, forty-two billion, four hundred thirty-one million, four hundred forty-one thousand, one hundred thirty-one".