13114413424041 has 4 divisors (see below), whose sum is σ = 17485884565392. Its totient is φ = 8742942282692.

The previous prime is 13114413424019. The next prime is 13114413424103. The reversal of 13114413424041 is 14042431441131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13114413424041 - 2¹⁰ = 13114413423017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13114413423993 and 13114413424011.

It is not an unprimeable number, because it can be changed into a prime (13114413424841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185735570671 + ... + 2185735570676.

It is an arithmetic number, because the mean of its divisors is an integer number (4371471141348).

Almost surely, 2^{13114413424041} is an apocalyptic number.

It is an amenable number.

13114413424041 is a deficient number, since it is larger than the sum of its proper divisors (4371471141351).

13114413424041 is an equidigital number, since it uses as much as digits as its factorization.

13114413424041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4371471141350.

The product of its (nonzero) digits is 18432, while the sum is 33.

Adding to 13114413424041 its reverse (14042431441131), we get a palindrome (27156844865172).

The spelling of 13114413424041 in words is "thirteen trillion, one hundred fourteen billion, four hundred thirteen million, four hundred twenty-four thousand, forty-one".