14042441412113 has 4 divisors (see below), whose sum is σ = 14043198313188. Its totient is φ = 14041684511040.

The previous prime is 14042441412061. The next prime is 14042441412133. The reversal of 14042441412113 is 31121414424041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7393923557329 + 6648517854784 = 2719177^2 + 2578472^2 .

It is a cyclic number.

It is not a de Polignac number, because 14042441412113 - 2³⁶ = 13973721935377 is a prime.

It is a super-2 number, since 2×14042441412113² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14042441412113.

It is not an unprimeable number, because it can be changed into a prime (14042441412133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 378422708 + ... + 378459813.

It is an arithmetic number, because the mean of its divisors is an integer number (3510799578297).

Almost surely, 2^{14042441412113} is an apocalyptic number.

It is an amenable number.

14042441412113 is a deficient number, since it is larger than the sum of its proper divisors (756901075).

14042441412113 is an equidigital number, since it uses as much as digits as its factorization.

14042441412113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 756901074.

The product of its (nonzero) digits is 12288, while the sum is 32.

Adding to 14042441412113 its reverse (31121414424041), we get a palindrome (45163855836154).

The spelling of 14042441412113 in words is "fourteen trillion, forty-two billion, four hundred forty-one million, four hundred twelve thousand, one hundred thirteen".