Base | Representation |
---|---|
bin | 11111111011100001110000… |
… | …110000000011000010010011 |
3 | 200102012222202001222010100000 |
4 | 133323201300300003002103 |
5 | 121401301412420303210 |
6 | 1214400414454301043 |
7 | 41402512561000635 |
oct | 3773416060030223 |
9 | 612188661863300 |
10 | 140430142353555 |
11 | 408220a8396a3a |
12 | 13900376657783 |
13 | 6048675a664b2 |
14 | 2696bd8792a55 |
15 | 1137d9c27cac0 |
hex | 7fb870c03093 |
140430142353555 has 48 divisors (see below), whose sum is σ = 252471207905280. Its totient is φ = 74883112136928.
The previous prime is 140430142353547. The next prime is 140430142353559. The reversal of 140430142353555 is 555353241034041.
140430142353555 is a `hidden beast` number, since 1 + 4 + 0 + 4 + 3 + 0 + 1 + 42 + 3 + 53 + 555 = 666.
It is not a de Polignac number, because 140430142353555 - 23 = 140430142353547 is a prime.
It is a super-2 number, since 2×1404301423535552 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a self number, because there is not a number n which added to its sum of digits gives 140430142353555.
It is not an unprimeable number, because it can be changed into a prime (140430142353559) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2978547 + ... + 17021516.
It is an arithmetic number, because the mean of its divisors is an integer number (5259816831360).
Almost surely, 2140430142353555 is an apocalyptic number.
140430142353555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
140430142353555 is a deficient number, since it is larger than the sum of its proper divisors (112041065551725).
140430142353555 is an equidigital number, since it uses as much as digits as its factorization.
140430142353555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20005862 (or 20005850 counting only the distinct ones).
The product of its (nonzero) digits is 2160000, while the sum is 45.
Adding to 140430142353555 its reverse (555353241034041), we get a palindrome (695783383387596).
The spelling of 140430142353555 in words is "one hundred forty trillion, four hundred thirty billion, one hundred forty-two million, three hundred fifty-three thousand, five hundred fifty-five".
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