14043040112131 has 4 divisors (see below), whose sum is σ = 14653607073552. Its totient is φ = 13432473150712.

The previous prime is 14043040112119. The next prime is 14043040112141. The reversal of 14043040112131 is 13121104034041.

14043040112131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14043040112131 - 2⁹ = 14043040111619 is a prime.

It is a super-2 number, since 2×14043040112131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14043040112096 and 14043040112105.

It is not an unprimeable number, because it can be changed into a prime (14043040112141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 305283480676 + ... + 305283480721.

It is an arithmetic number, because the mean of its divisors is an integer number (3663401768388).

Almost surely, 2^{14043040112131} is an apocalyptic number.

14043040112131 is a deficient number, since it is larger than the sum of its proper divisors (610566961421).

14043040112131 is an equidigital number, since it uses as much as digits as its factorization.

14043040112131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 610566961420.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14043040112131 its reverse (13121104034041), we get a palindrome (27164144146172).

The spelling of 14043040112131 in words is "fourteen trillion, forty-three billion, forty million, one hundred twelve thousand, one hundred thirty-one".