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140432113103122 = 270216056551561
BaseRepresentation
bin11111111011100011100110…
…001101110111000100010010
3200102020011211102021120111201
4133323203212031313010102
5121401314431423244442
61214401342214301414
741402612451045331
oct3773434615670422
9612204742246451
10140432113103122
1140822a19875295
121390082665786a
1360488cb13bab9
142696d443d5d18
151137e652b37b7
hex7fb8e6377112

140432113103122 has 4 divisors (see below), whose sum is σ = 210648169654686. Its totient is φ = 70216056551560.

The previous prime is 140432113103039. The next prime is 140432113103123. The reversal of 140432113103122 is 221301311234041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 119403459441721 + 21028653661401 = 10927189^2 + 4585701^2 .

It is a super-2 number, since 2×1404321131031222 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (140432113103123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35108028275779 + ... + 35108028275782.

Almost surely, 2140432113103122 is an apocalyptic number.

140432113103122 is a deficient number, since it is larger than the sum of its proper divisors (70216056551564).

140432113103122 is an equidigital number, since it uses as much as digits as its factorization.

140432113103122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70216056551563.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 140432113103122 its reverse (221301311234041), we get a palindrome (361733424337163).

The spelling of 140432113103122 in words is "one hundred forty trillion, four hundred thirty-two billion, one hundred thirteen million, one hundred three thousand, one hundred twenty-two".

Divisors: 1 2 70216056551561 140432113103122