Base | Representation |
---|---|
bin | 11111111011100011100110… |
… | …001101110111000100010010 |
3 | 200102020011211102021120111201 |
4 | 133323203212031313010102 |
5 | 121401314431423244442 |
6 | 1214401342214301414 |
7 | 41402612451045331 |
oct | 3773434615670422 |
9 | 612204742246451 |
10 | 140432113103122 |
11 | 40822a19875295 |
12 | 1390082665786a |
13 | 60488cb13bab9 |
14 | 2696d443d5d18 |
15 | 1137e652b37b7 |
hex | 7fb8e6377112 |
140432113103122 has 4 divisors (see below), whose sum is σ = 210648169654686. Its totient is φ = 70216056551560.
The previous prime is 140432113103039. The next prime is 140432113103123. The reversal of 140432113103122 is 221301311234041.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 119403459441721 + 21028653661401 = 10927189^2 + 4585701^2 .
It is a super-2 number, since 2×1404321131031222 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (140432113103123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35108028275779 + ... + 35108028275782.
Almost surely, 2140432113103122 is an apocalyptic number.
140432113103122 is a deficient number, since it is larger than the sum of its proper divisors (70216056551564).
140432113103122 is an equidigital number, since it uses as much as digits as its factorization.
140432113103122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70216056551563.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 140432113103122 its reverse (221301311234041), we get a palindrome (361733424337163).
The spelling of 140432113103122 in words is "one hundred forty trillion, four hundred thirty-two billion, one hundred thirteen million, one hundred three thousand, one hundred twenty-two".
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