Base | Representation |
---|---|
bin | 11010001010000101… |
… | …01011101101101011 |
3 | 1100020200211011021121 |
4 | 31011002223231223 |
5 | 212230031430011 |
6 | 10241255120111 |
7 | 1005001340434 |
oct | 150502535553 |
9 | 40220734247 |
10 | 14043233131 |
11 | 5a570479a4 |
12 | 287b073037 |
13 | 142a568205 |
14 | 97312c48b |
15 | 572d22e71 |
hex | 3450abb6b |
14043233131 has 4 divisors (see below), whose sum is σ = 14369819992. Its totient is φ = 13716646272.
The previous prime is 14043233111. The next prime is 14043233147. The reversal of 14043233131 is 13133234041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14043233131 - 27 = 14043233003 is a prime.
It is a super-2 number, since 2×140432331312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14043233096 and 14043233105.
It is not an unprimeable number, because it can be changed into a prime (14043233111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163293366 + ... + 163293451.
It is an arithmetic number, because the mean of its divisors is an integer number (3592454998).
Almost surely, 214043233131 is an apocalyptic number.
14043233131 is a deficient number, since it is larger than the sum of its proper divisors (326586861).
14043233131 is an equidigital number, since it uses as much as digits as its factorization.
14043233131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 326586860.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 14043233131 its reverse (13133234041), we get a palindrome (27176467172).
The spelling of 14043233131 in words is "fourteen billion, forty-three million, two hundred thirty-three thousand, one hundred thirty-one".
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