Base | Representation |
---|---|
bin | 11010001010000110… |
… | …00001000010000111 |
3 | 1100020200222121001211 |
4 | 31011003001002013 |
5 | 212230042223310 |
6 | 10241301032251 |
7 | 1005002153143 |
oct | 150503010207 |
9 | 40220877054 |
10 | 14043320455 |
11 | 5a570a756a |
12 | 287b0b5687 |
13 | 142a598b98 |
14 | 973152223 |
15 | 572d3dc8a |
hex | 3450c1087 |
14043320455 has 8 divisors (see below), whose sum is σ = 16864768800. Its totient is φ = 11226133536.
The previous prime is 14043320449. The next prime is 14043320521. The reversal of 14043320455 is 55402334041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14043320455 - 27 = 14043320327 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1058100 + ... + 1071289.
It is an arithmetic number, because the mean of its divisors is an integer number (2108096100).
Almost surely, 214043320455 is an apocalyptic number.
14043320455 is a deficient number, since it is larger than the sum of its proper divisors (2821448345).
14043320455 is a wasteful number, since it uses less digits than its factorization.
14043320455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2130713.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 14043320455 its reverse (55402334041), we get a palindrome (69445654496).
The spelling of 14043320455 in words is "fourteen billion, forty-three million, three hundred twenty thousand, four hundred fifty-five".
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