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140433221121 = 3172753592571
BaseRepresentation
bin1000001011001001111…
…0001110011000000001
3111102111000212210101220
42002302132032120001
54300101401033441
6144303015145253
713101031453434
oct2026236163001
9442430783356
10140433221121
115461498a626
1223272975229
131032056575b
146b22d9d81b
1539bdc98466
hex20b278e601

140433221121 has 8 divisors (see below), whose sum is σ = 198258665184. Its totient is φ = 88114962240.

The previous prime is 140433221111. The next prime is 140433221141. The reversal of 140433221121 is 121122334041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-140433221121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140433221091 and 140433221100.

It is not an unprimeable number, because it can be changed into a prime (140433221111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1376796235 + ... + 1376796336.

It is an arithmetic number, because the mean of its divisors is an integer number (24782333148).

Almost surely, 2140433221121 is an apocalyptic number.

It is an amenable number.

140433221121 is a deficient number, since it is larger than the sum of its proper divisors (57825444063).

140433221121 is a wasteful number, since it uses less digits than its factorization.

140433221121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2753592591.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 140433221121 its reverse (121122334041), we get a palindrome (261555555162).

The spelling of 140433221121 in words is "one hundred forty billion, four hundred thirty-three million, two hundred twenty-one thousand, one hundred twenty-one".

Divisors: 1 3 17 51 2753592571 8260777713 46811073707 140433221121