140440101320041 has 4 divisors (see below), whose sum is σ = 140498206453332. Its totient is φ = 140381996186752.

The previous prime is 140440101320017. The next prime is 140440101320093. The reversal of 140440101320041 is 140023101044041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 99365589396441 + 41074511923600 = 9968229^2 + 6408940^2 .

It is a cyclic number.

It is not a de Polignac number, because 140440101320041 - 2¹⁷ = 140440101188969 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140440101319988 and 140440101320015.

It is not an unprimeable number, because it can be changed into a prime (140440101320341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29052563020 + ... + 29052567853.

It is an arithmetic number, because the mean of its divisors is an integer number (35124551613333).

Almost surely, 2^{140440101320041} is an apocalyptic number.

It is an amenable number.

140440101320041 is a deficient number, since it is larger than the sum of its proper divisors (58105133291).

140440101320041 is an equidigital number, since it uses as much as digits as its factorization.

140440101320041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58105133290.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 140440101320041 its reverse (140023101044041), we get a palindrome (280463202364082).

The spelling of 140440101320041 in words is "one hundred forty trillion, four hundred forty billion, one hundred one million, three hundred twenty thousand, forty-one".