14044031111 has 4 divisors (see below), whose sum is σ = 15320761224. Its totient is φ = 12767301000.

The previous prime is 14044031087. The next prime is 14044031161. The reversal of 14044031111 is 11113044041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14044031111 - 2¹⁰ = 14044030087 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14044031161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 638365040 + ... + 638365061.

It is an arithmetic number, because the mean of its divisors is an integer number (3830190306).

Almost surely, 2^14044031111 is an apocalyptic number.

14044031111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

14044031111 is a deficient number, since it is larger than the sum of its proper divisors (1276730113).

14044031111 is a wasteful number, since it uses less digits than its factorization.

14044031111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1276730112.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 14044031111 its reverse (11113044041), we get a palindrome (25157075152).

The spelling of 14044031111 in words is "fourteen billion, forty-four million, thirty-one thousand, one hundred eleven".