14044043113 has 4 divisors (see below), whose sum is σ = 14099995728. Its totient is φ = 13988090500.

The previous prime is 14044043089. The next prime is 14044043129. The reversal of 14044043113 is 31134044041.

14044043113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31134044041 = 157 ⋅198306013.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14044043113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14044043813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27975931 + ... + 27976432.

It is an arithmetic number, because the mean of its divisors is an integer number (3524998932).

Almost surely, 2^14044043113 is an apocalyptic number.

It is an amenable number.

14044043113 is a deficient number, since it is larger than the sum of its proper divisors (55952615).

14044043113 is an equidigital number, since it uses as much as digits as its factorization.

14044043113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55952614.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14044043113 its reverse (31134044041), we get a palindrome (45178087154).

The spelling of 14044043113 in words is "fourteen billion, forty-four million, forty-three thousand, one hundred thirteen".