Base | Representation |
---|---|
bin | 1000001011001011110… |
… | …0010100011001100011 |
3 | 111102111120201121001212 |
4 | 2002302330110121203 |
5 | 4300110411010430 |
6 | 144303500220335 |
7 | 13101155511425 |
oct | 2026274243143 |
9 | 442446647055 |
10 | 140441110115 |
11 | 54619388759 |
12 | 2327553a6ab |
13 | 103220984b7 |
14 | 6b24054815 |
15 | 39be805b95 |
hex | 20b2f14663 |
140441110115 has 4 divisors (see below), whose sum is σ = 168529332144. Its totient is φ = 112352888088.
The previous prime is 140441110099. The next prime is 140441110181. The reversal of 140441110115 is 511011144041.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511011144041 = 257003 ⋅1988347.
It is a cyclic number.
It is not a de Polignac number, because 140441110115 - 24 = 140441110099 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14044111007 + ... + 14044111016.
It is an arithmetic number, because the mean of its divisors is an integer number (42132333036).
Almost surely, 2140441110115 is an apocalyptic number.
140441110115 is a deficient number, since it is larger than the sum of its proper divisors (28088222029).
140441110115 is an equidigital number, since it uses as much as digits as its factorization.
140441110115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28088222028.
The product of its (nonzero) digits is 320, while the sum is 23.
Adding to 140441110115 its reverse (511011144041), we get a palindrome (651452254156).
The spelling of 140441110115 in words is "one hundred forty billion, four hundred forty-one million, one hundred ten thousand, one hundred fifteen".
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