Base | Representation |
---|---|
bin | 1000001011001011110… |
… | …0011001100001101001 |
3 | 111102111120202122212120 |
4 | 2002302330121201221 |
5 | 4300110412143423 |
6 | 144303500501453 |
7 | 13101155626563 |
oct | 2026274314151 |
9 | 442446678776 |
10 | 140441131113 |
11 | 546193a2508 |
12 | 2327554a889 |
13 | 103220a4c1a |
14 | 6b2405c333 |
15 | 39be80bee3 |
hex | 20b2f19869 |
140441131113 has 8 divisors (see below), whose sum is σ = 187664591328. Its totient is φ = 93422545824.
The previous prime is 140441131087. The next prime is 140441131157. The reversal of 140441131113 is 311131144041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 140441131113 - 212 = 140441127017 is a prime.
It is a super-2 number, since 2×1404411311132 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (140441131513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 51217131 + ... + 51219872.
It is an arithmetic number, because the mean of its divisors is an integer number (23458073916).
Almost surely, 2140441131113 is an apocalyptic number.
It is an amenable number.
140441131113 is a deficient number, since it is larger than the sum of its proper divisors (47223460215).
140441131113 is a wasteful number, since it uses less digits than its factorization.
140441131113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 102437463.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 140441131113 its reverse (311131144041), we get a palindrome (451572275154).
The spelling of 140441131113 in words is "one hundred forty billion, four hundred forty-one million, one hundred thirty-one thousand, one hundred thirteen".
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