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140442331201 = 267152580431
BaseRepresentation
bin1000001011001100000…
…0111110100001000001
3111102111200000122002021
42002303000332201001
54300111214044301
6144303542321441
713101202055434
oct2026300764101
9442450018067
10140442331201
115461a042117
1223275a29281
1310322405233
146b2429181b
1539be9978a1
hex20b303e841

140442331201 has 4 divisors (see below), whose sum is σ = 140494914304. Its totient is φ = 140389748100.

The previous prime is 140442331177. The next prime is 140442331207. The reversal of 140442331201 is 102133244041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140442331201 - 219 = 140441806913 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140442331207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26287545 + ... + 26292886.

It is an arithmetic number, because the mean of its divisors is an integer number (35123728576).

Almost surely, 2140442331201 is an apocalyptic number.

It is an amenable number.

140442331201 is a deficient number, since it is larger than the sum of its proper divisors (52583103).

140442331201 is an equidigital number, since it uses as much as digits as its factorization.

140442331201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 52583102.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 140442331201 its reverse (102133244041), we get a palindrome (242575575242).

The spelling of 140442331201 in words is "one hundred forty billion, four hundred forty-two million, three hundred thirty-one thousand, two hundred one".

Divisors: 1 2671 52580431 140442331201