14044401313 has 4 divisors (see below), whose sum is σ = 14084875440. Its totient is φ = 14003927188.

The previous prime is 14044401311. The next prime is 14044401337. The reversal of 14044401313 is 31310444041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31310444041 = 67181 ⋅466061.

It is a cyclic number.

It is not a de Polignac number, because 14044401313 - 2¹ = 14044401311 is a prime.

It is a super-2 number, since 2×14044401313² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14044401311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20236543 + ... + 20237236.

It is an arithmetic number, because the mean of its divisors is an integer number (3521218860).

Almost surely, 2^14044401313 is an apocalyptic number.

It is an amenable number.

14044401313 is a deficient number, since it is larger than the sum of its proper divisors (40474127).

14044401313 is an equidigital number, since it uses as much as digits as its factorization.

14044401313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40474126.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14044401313 its reverse (31310444041), we get a palindrome (45354845354).

The spelling of 14044401313 in words is "fourteen billion, forty-four million, four hundred one thousand, three hundred thirteen".