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140500115244332 = 22342337102603659
BaseRepresentation
bin11111111100100010111011…
…011101011100010100101100
3200102110200100121022021100022
4133330202323131130110230
5121403423214000304312
61214452510100221312
741410540555521644
oct3774427335342454
9612420317267308
10140500115244332
1140849845252498
1213911a4439a838
1360521476ab88c
14269a35594d524
151139ae52d6172
hex7fc8bb75c52c

140500115244332 has 12 divisors (see below), whose sum is σ = 245875922299560. Its totient is φ = 70249851730176.

The previous prime is 140500115244317. The next prime is 140500115244389. The reversal of 140500115244332 is 233442511005041.

It is a junction number, because it is equal to n+sod(n) for n = 140500115244292 and 140500115244301.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49932482 + ... + 52671177.

It is an arithmetic number, because the mean of its divisors is an integer number (20489660191630).

Almost surely, 2140500115244332 is an apocalyptic number.

It is an amenable number.

140500115244332 is a deficient number, since it is larger than the sum of its proper divisors (105375807055228).

140500115244332 is a wasteful number, since it uses less digits than its factorization.

140500115244332 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 102946000 (or 102945998 counting only the distinct ones).

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 140500115244332 its reverse (233442511005041), we get a palindrome (373942626249373).

The spelling of 140500115244332 in words is "one hundred forty trillion, five hundred billion, one hundred fifteen million, two hundred forty-four thousand, three hundred thirty-two".

Divisors: 1 2 4 342337 684674 1369348 102603659 205207318 410414636 35125028811083 70250057622166 140500115244332