14050133311 has 4 divisors (see below), whose sum is σ = 14050594000. Its totient is φ = 14049672624.

The previous prime is 14050133297. The next prime is 14050133323. The reversal of 14050133311 is 11333105041.

14050133311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11333105041 = 1453 ⋅7799797.

It is a cyclic number.

It is not a de Polignac number, because 14050133311 - 2¹³ = 14050125119 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14050134311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 181086 + ... + 246763.

It is an arithmetic number, because the mean of its divisors is an integer number (3512648500).

Almost surely, 2^14050133311 is an apocalyptic number.

14050133311 is a deficient number, since it is larger than the sum of its proper divisors (460689).

14050133311 is an equidigital number, since it uses as much as digits as its factorization.

14050133311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 460688.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 14050133311 its reverse (11333105041), we get a palindrome (25383238352).

The spelling of 14050133311 in words is "fourteen billion, fifty million, one hundred thirty-three thousand, three hundred eleven".