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140503123024231 = 113105562075901
BaseRepresentation
bin11111111100100101101110…
…101111001101100101100111
3200102110222010012222022200211
4133330211232233031211213
5121404000343443233411
61214454124343320251
741411005240316362
oct3774455657154547
9612428105868624
10140503123024231
1140850049047000
1213912543750087
1360525068882b6
14269a55d1bd0d9
151139c1e3b5221
hex7fc96ebcd967

140503123024231 has 8 divisors (see below), whose sum is σ = 154542879120528. Its totient is φ = 127730111839000.

The previous prime is 140503123024207. The next prime is 140503123024259. The reversal of 140503123024231 is 132420321305041.

It is not a de Polignac number, because 140503123024231 - 245 = 105318750935399 is a prime.

It is a super-2 number, since 2×1405031230242312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140503123024193 and 140503123024202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140503123024331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52781036620 + ... + 52781039281.

It is an arithmetic number, because the mean of its divisors is an integer number (19317859890066).

Almost surely, 2140503123024231 is an apocalyptic number.

140503123024231 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

140503123024231 is a deficient number, since it is larger than the sum of its proper divisors (14039756096297).

140503123024231 is an equidigital number, since it uses as much as digits as its factorization.

140503123024231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105562075934 (or 105562075912 counting only the distinct ones).

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 140503123024231 its reverse (132420321305041), we get a palindrome (272923444329272).

The spelling of 140503123024231 in words is "one hundred forty trillion, five hundred three billion, one hundred twenty-three million, twenty-four thousand, two hundred thirty-one".

Divisors: 1 11 121 1331 105562075901 1161182834911 12773011184021 140503123024231