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140504214603 = 346834738201
BaseRepresentation
bin1000001011011010110…
…1000010110001001011
3111102122222110122011010
42002312231002301023
54300223034331403
6144314032535003
713102553055504
oct2026655026113
9442588418133
10140504214603
1154650a6a025
12232926b1463
131033219152c
146b2c59dbab
1539c511d603
hex20b6b42c4b

140504214603 has 4 divisors (see below), whose sum is σ = 187338952808. Its totient is φ = 93669476400.

The previous prime is 140504214581. The next prime is 140504214611. The reversal of 140504214603 is 306412405041.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 140504214603 - 213 = 140504206411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140504214623) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23417369098 + ... + 23417369103.

It is an arithmetic number, because the mean of its divisors is an integer number (46834738202).

Almost surely, 2140504214603 is an apocalyptic number.

140504214603 is a deficient number, since it is larger than the sum of its proper divisors (46834738205).

140504214603 is an equidigital number, since it uses as much as digits as its factorization.

140504214603 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46834738204.

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 140504214603 its reverse (306412405041), we get a palindrome (446916619644).

The spelling of 140504214603 in words is "one hundred forty billion, five hundred four million, two hundred fourteen thousand, six hundred three".

Divisors: 1 3 46834738201 140504214603