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14051104051 = 31453261421
BaseRepresentation
bin11010001011000001…
…01101010100110011
31100021020122001011011
431011200231110303
5212234040312201
610242135531351
71005125261635
oct150540552463
940236561134
1014051104051
115a60533496
122881829b57
13142c09296a
149741baa55
1557387a151
hex34582d533

14051104051 has 4 divisors (see below), whose sum is σ = 14504365504. Its totient is φ = 13597842600.

The previous prime is 14051104033. The next prime is 14051104079. The reversal of 14051104051 is 15040115041.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14051104051 - 211 = 14051102003 is a prime.

It is a super-2 number, since 2×140511040512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14051104031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226630680 + ... + 226630741.

It is an arithmetic number, because the mean of its divisors is an integer number (3626091376).

Almost surely, 214051104051 is an apocalyptic number.

14051104051 is a deficient number, since it is larger than the sum of its proper divisors (453261453).

14051104051 is an equidigital number, since it uses as much as digits as its factorization.

14051104051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 453261452.

The product of its (nonzero) digits is 400, while the sum is 22.

Adding to 14051104051 its reverse (15040115041), we get a palindrome (29091219092).

The spelling of 14051104051 in words is "fourteen billion, fifty-one million, one hundred four thousand, fifty-one".

Divisors: 1 31 453261421 14051104051