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140522130433 = 615192284207
BaseRepresentation
bin1000001011011111000…
…1011000110000000001
3111102201020011212001101
42002313301120300001
54300242131133213
6144315512534401
713103161254316
oct2026761306001
9442636155041
10140522130433
11546600964a3
12232986b1401
1310335ac5109
146b30b04d0d
1539c69abbdd
hex20b7c58c01

140522130433 has 4 divisors (see below), whose sum is σ = 140524476160. Its totient is φ = 140519784708.

The previous prime is 140522130409. The next prime is 140522130491. The reversal of 140522130433 is 334031225041.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140522130433 - 217 = 140521999361 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140522130493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1080585 + ... + 1203622.

It is an arithmetic number, because the mean of its divisors is an integer number (35131119040).

Almost surely, 2140522130433 is an apocalyptic number.

It is an amenable number.

140522130433 is a deficient number, since it is larger than the sum of its proper divisors (2345727).

140522130433 is an equidigital number, since it uses as much as digits as its factorization.

140522130433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2345726.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 140522130433 its reverse (334031225041), we get a palindrome (474553355474).

The spelling of 140522130433 in words is "one hundred forty billion, five hundred twenty-two million, one hundred thirty thousand, four hundred thirty-three".

Divisors: 1 61519 2284207 140522130433