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14052351140051 = 76969128805423
BaseRepresentation
bin1100110001111101000101…
…1001011110000011010011
31211202101120111211102012112
43030133101121132003103
53320213203342440201
645515321101415535
72650151234611040
oct314372131360323
954671514742175
1014052351140051
114528628968a94
1216ab533b6a5ab
137ac191b330b3
143681cd1401c7
15195801db70bb
hexcc7d165e0d3

14052351140051 has 8 divisors (see below), whose sum is σ = 16060060875264. Its totient is φ = 12044699155080.

The previous prime is 14052351140029. The next prime is 14052351140057. The reversal of 14052351140051 is 15004115325041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14052351140051 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14052351140057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13914875 + ... + 14890548.

It is an arithmetic number, because the mean of its divisors is an integer number (2007507609408).

Almost surely, 214052351140051 is an apocalyptic number.

14052351140051 is a deficient number, since it is larger than the sum of its proper divisors (2007709735213).

14052351140051 is an equidigital number, since it uses as much as digits as its factorization.

14052351140051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28875121.

The product of its (nonzero) digits is 12000, while the sum is 32.

Adding to 14052351140051 its reverse (15004115325041), we get a palindrome (29056466465092).

The spelling of 14052351140051 in words is "fourteen trillion, fifty-two billion, three hundred fifty-one million, one hundred forty thousand, fifty-one".

Divisors: 1 7 69691 487837 28805423 201637961 2007478734293 14052351140051